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计算工作时间的SQL

发表于:2017-08-08 作者:网络转载 来源:

  排除非工作时间、非工作日后,计算工作时间,代码如下:
-- 删除函数
DROP FUNCTION IF EXISTS calculateWorkingTime;
set @workStartTime='09:30:00';
set @workEndTime='18:30:00';
-- 创建函数
--/
CREATE FUNCTION calculateWorkingTime(startDate datetime,endDate datetime)
RETURNS decimal(32,4)
BEGIN
DECLARE intnum int(255) DEFAULT 0;
DECLARE decimalnum decimal(32,4) DEFAULT 0.000;
DECLARE workStartTimeHour decimal(32,4) DEFAULT 0.000;
DECLARE workEndTimeHour decimal(32,4) DEFAULT 0.000;
DECLARE currentDay int(10) DEFAULT 0;
DECLARE tempTimeHour decimal(32,4) DEFAULT 0.000;
-- DECLARE temp varchar(2048) DEFAULT '';
-- deal starttime and endtime is nonworkdays
SET startDate = (CASE WHEN weekday(startDate)=5 THEN concat(date(timestampadd(day,2,startDate)),' ',@workStartTime) WHEN weekday(startDate)=6 THEN concat(date(timestampadd(day,1,startDate)),' ',@workStartTime) ELSE startDate END);
SET endDate = (CASE WHEN weekday(endDate)=5 THEN concat(date(timestampadd(day,-1,endDate)),' ',@workEndTime) WHEN weekday(endDate)=6 THEN concat(date(timestampadd(day,-2,endDate)),' ',@workEndTime) ELSE endDate END);
--  SET temp = concat(temp,' ',startDate,';',endDate);
if startDate < endDate then
-- deal starttime and endtime is nonworktime
if time(startDate)<=@workStartTime THEN
SET startDate = concat(date(startDate),' ', @workStartTime);
elseif date(startDate) < date(endDate) and time(startDate)>@workEndTime then
SET startDate = concat(date(date_add(startDate, interval 1 day)),' ',@workStartTime);
end if;
if time(endDate)>=@workEndTime then
SET endDate = concat(date(endDate),' ',@workEndTime);
elseif date(startDate) < date(endDate) and time(endDate)<@workStartTime then
SET endDate = concat(date(date_add(endDate, interval -1 day)),' ',@workEndTime);
end if;
-- calculate time diff
SET decimalnum = (minute(endDate)*60+second(endDate)-minute(startDate)*60-second(startDate))/3600;
end if;
-- calculate work time second
SET workStartTimeHour = hour(@workStartTime)+minute(@workStartTime)/60+second(@workStartTime)/3600;
SET workEndTimeHour = hour(@workEndTime)+minute(@workEndTime)/60+second(@workEndTime)/3600;
--  WHILE (floor((unix_timestamp(endDate) - unix_timestamp(startDate))/3600) > 0) DO
WHILE ((floor(unix_timestamp(endDate)/3600) - floor(unix_timestamp(startDate)/3600)) > 0) DO
SET tempTimeHour = hour(startDate)+minute(startDate)/60+second(startDate)/3600;
if   workStartTimeHour <= tempTimeHour and tempTimeHour < workEndTimeHour then
--   SET temp = concat(temp,' ',tempTimeHour,';');
SET intnum = (CASE WHEN weekday(startDate)=5 or weekday(startDate)=6 then intnum ELSE intnum+1 END);
end if;
SET startDate = timestampadd(hour,1,startDate);
END WHILE;
SET decimalnum = intnum + decimalnum;
-- concat(decimalnum,';',workStartTimeHour,' ',workEndTimeHour,' ',intnum,';;;',temp);
RETURN decimalnum;
END
/
-- select calculateWorkingTime('2017-02-17 07:30:00','2017-02-21 17:39:00');
select transport_id,create_at1,create_at2,create_at3, calculateWorkingTime(create_at1,create_at2), calculateWorkingTime(create_at2,create_at3),calculateWorkingTime(create_at1,create_at3) from newTable;
select transport_id,calculateWorkingTime(create_at1,create_at2) from newTable;
  说明:第一次实现这种需求,当初写的时候又比较赶,写完后,发现,虽然功能实现了,但还有好多地方可以调优
  女票是搞数据运营的,经常需要统计员工的工作时间;听女票说,这段SQL代码统计时好像有些问题,但还没来的急分析原因呢;女票又有新需求来了,不仅需要将非工作时间、非工作日去掉,还需要将节假日去掉   我将上面代码重构,实现想要功能(重构后的代码就不放出了)